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Asked in GSEB Board March 2022 · Brewster's law and polarisation by reflection
Given: unpolarised light on glass of μ=1.5, with the reflected and refracted rays at right angles.
Idea: with the reflected ray at i and the refracted ray at r from the normal, the angle between them is 180°-(i+r). Setting that to 90° gives i+r=90°, and substituting r=90°-i in Snell's law gives Brewster's law, tan iₚ=μ.
iₚ=tan⁻¹1.5.
tan⁻¹1.5=56.3°.
iₚ≈57°.
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