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The distance between the two slits in Young's experiment is 0.2 mm. If the wavelength of the light is 5000 A, the angular position of the third bright fringe from the central bright fringe is

Asked in GSEB Board March 2019 · Fringe width and fringe position

Answer: (3) 0.0075 rad

Step-by-step solution

Given: d=0.2 mm=2×10⁻⁴ m, λ=5000 A=5×10⁻⁷ m, order n=3.

Idea: a bright fringe needs a path difference of a whole number of wavelengths, d sin θ=nλ, and for fringes this close to the centre sin θ≈θ.

θ=(nλ)/d=(3×5×10⁻⁷)/(2×10⁻⁴).

=(1.5×10⁻⁶)/(2×10⁻⁴).

θ=7.5×10⁻³.

θ=0.0075 rad.

Why the other options are wrong

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