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Asked in GUJCET 2015 · Single slit diffraction
Given: slit of width d, wavelength λ, screen at distance D, and a central maximum as wide as the slit.
Idea: the first minima of a single slit lie at sin θ=±λ/d, so on the screen the central maximum has linear width (2λ D)/d.
Set that equal to the slit width: (2λ D)/d=d.
2λ D=d².
D=(d²)/(2λ).
Check the sense of it: a narrower slit needs a nearer screen for the patch of light to stay as narrow as the slit.
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