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Light of wavelength λ is incident on a slit of width d. The resulting diffraction pattern is observed on a screen placed at a distance D from the slit. If the linear width of the central maximum equals the width of the slit, then D=

Asked in GUJCET 2015 · Single slit diffraction

Answer: (2) (d²)/(2λ)

Step-by-step solution

Given: slit of width d, wavelength λ, screen at distance D, and a central maximum as wide as the slit.

Idea: the first minima of a single slit lie at sin θ=±λ/d, so on the screen the central maximum has linear width (2λ D)/d.

Set that equal to the slit width: (2λ D)/d=d.

2λ D=d².

D=(d²)/(2λ).

Check the sense of it: a narrower slit needs a nearer screen for the patch of light to stay as narrow as the slit.

Why the other options are wrong

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