Practice portal › Wave Optics › Interference and Young's Double Slit Experiment
Asked in GUJCET 2011 · Slabs, media and modified set-ups
Given: the whole interference set-up is moved from air into water of refractive index n.
Idea: the fringe width is β=(λ D)/d, and inside a medium the wavelength becomes λ_w=λ/n.
The slit separation d and the screen distance D belong to the apparatus, so they do not change.
β_w=(λ D)/(nd)=β/n, and n>1 for water.
So the fringe width decreases, by the factor n (about 4/3 for water).
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