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Asked in RS Academy GUJCET booklet · Lens maker's formula and power
Given: a thin convex glass lens with one curved surface of radius R=20 cm, n=1.5, in air. The printed hint fixes the form to use: 1/f=(n-1)/R.
Idea: every refracting surface adds (n-1)/R to the power of the lens. Here that term appears once, so the lens is half as strong as a double convex lens of the same radius.
1/f=(1.5-1)/(20)=(0.5)/(20).
That is 1/f=1/(40).
So the focal length is f=40 cm.
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