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Consider a refracting telescope whose objective has a focal length of 1 m and the eyepiece a focal length of 1 cm, then magnifying power of this telescope will be ________.

Asked in GUJCET 2024 · Telescopes

Answer: (4) 100

Step-by-step solution

Given: fₒ=1 m for the objective and fₑ=1 cm for the eyepiece.

Idea: in normal adjustment a refracting telescope magnifies by m=(fₒ)/(fₑ), with both focal lengths in the same unit.

fₒ=1 m=100 cm

m=(100 cm)/(1 cm)=100

The whole art of a telescope is in that ratio: a long objective and a short eyepiece.

Why the other options are wrong

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