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Asked in GSEB Board March 2023 · Mass defect and binding energy
Given: E=9×10¹³ J and c=3×10⁸ m/s.
Idea: rearrange E=mc² into m=E/(c²). 'Maximum mass' because at best all the energy becomes mass.
c²=(3×10⁸)²=9×10¹⁶ m² s⁻².
m=(9×10¹³)/(9×10¹⁶)=10⁻³ kg.
10⁻³ kg=1 g — the same pairing as the standard result that 1 g is worth 9×10¹³ J, read backwards.
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