The magnetic susceptibility of a paramagnetic material is 1.0×10⁻⁵ at 27°C temperature. Then, at what temperature its magnetic susceptibility would be 1.5×10⁻⁵ ?

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Accepted Answer

(3) -73°C. Given: χ₁=1.0×10⁻⁵ at T₁=27°C=300 K, and χ₂=1.5×10⁻⁵. Idea: for a paramagnet Curie's law says χ=C/T with T in kelvin, so the product χ T is the same at both temperatures. χ₁T₁=χ₂T₂ T₂=(χ₁T₁)/(χ₂)=((1.0×10⁻⁵)(300))/(1.5×10⁻⁵)=200 K. Sense check: a larger susceptibility means less thermal disorder, so the sample must be colder -- and 200 K is indeed below 300 K. Back to Celsius: 200-273=-73, so the temperature is -73°C.

The magnetic susceptibility of a paramagnetic material is 1.0×10⁻⁵ at 27°C temperature. Then, at what temperature its magnetic susceptibility would be 1.5×10⁻⁵ ?

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