Practice portal › Moving Charges and Magnetism › Motion of a Charge in a Magnetic Field
Asked in RS Academy GUJCET booklet · Circular motion: radius, period and energy
Idea: the magnetic force supplies the centripetal force for the circular path, qvB=(mv²)/r.
Solving for the radius: r=(mv)/(qB).
With the charge, the mass and the field fixed, r is proportional to the speed.
So increasing the speed increases the radius of curvature, while the period T=(2π m)/(qB) stays exactly the same.
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