Practice portal › Moving Charges and Magnetism › Motion of a Charge in a Magnetic Field

What is the frequency of an electron (mass 9×10⁻³¹ kg and charge 1.6×10⁻¹⁹ C) moving at a speed of 3×10⁷ m s⁻¹ in a magnetic field of 4×10⁻⁴ T perpendicular to it?

Asked in GSEB Board August 2020 · Circular motion: radius, period and energy

Answer: (1) 11.32 MHz

Step-by-step solution

Given: m=9×10⁻³¹ kg, e=1.6×10⁻¹⁹ C, B=4×10⁻⁴ T perpendicular to the velocity.

Idea: the time for one revolution is T=(2π m)/(eB), which carries no speed in it, so the 3×10⁷ m s⁻¹ is not needed. The frequency is f=1/T=(eB)/(2π m).

Top: 1.6×10⁻¹⁹×4×10⁻⁴=6.4×10⁻²³.

Bottom: 2π×9×10⁻³¹=5.65×10⁻³⁰.

f=(6.4×10⁻²³)/(5.65×10⁻³⁰)=1.132×10⁷ Hz=11.32 MHz.

Why the other options are wrong

More Motion of a Charge in a Magnetic Field questionsAll Motion of a Charge in a Magnetic Field questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer