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A solenoid of length 0.5 m has a radius of 1 cm and is made up of 500 turns. It carries a current of 6 A. What is the magnitude of the magnetic field inside the solenoid ?

Asked in GSEB Board August 2020 · Solenoid, toroid and field energy

Answer: (1) 24π×10⁻⁴ T

Step-by-step solution

Given: L=0.5 m, N=500 turns, I=6 A. The radius 1 cm plays no part — the field inside a long solenoid does not depend on it.

Idea: B=μ₀ nI, with n the number of turns per metre.

n=(500)/(0.5)=1000 m⁻¹.

B=4π×10⁻⁷×1000×6=24π×10⁻⁴ T.

Numerically that is about 7.5×10⁻³ T.

Why the other options are wrong

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