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Asked in GSEB Board March 2020 · Rotating charges and multiple loops
Given: N=100 turns, R=2 cm=0.02 m, I=0.20 A.
Idea: at the centre of a circular coil the N turns add up, B=(μ₀NI)/(2R).
B=(4π×10⁻⁷×100×0.20)/(2×0.02).
Numerator =8π×10⁻⁶, denominator =0.04.
B=2π×10⁻⁴ T, about 6.28×10⁻⁴ T.
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