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Asked in GUJCET 2023 · Conversion to ammeter and voltmeter
Given: galvanometer resistance G=18 Ω; the range is to be multiplied by n=10.
Idea: a shunt in parallel carries the current the coil must not, and being in parallel the two have the same voltage across them.
At full scale the coil still takes I_g while the line carries I=nI_g, so the shunt carries (n-1)I_g.
Equal voltages: I_g G=(n-1)I_g S, so S=G/(n-1).
S=(18)/(10-1)=2 Ω.
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