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A charged particle is moving in a uniform magnetic field. Then ______.

Asked in GUJCET 2016 · Lorentz force and work done

Answer: (2) its momentum changes but kinetic energy does not change

Step-by-step solution

Idea: the magnetic force on a moving charge is ⃗F=q⃗v×⃗B, and a cross product is perpendicular to both its factors.

Work: dW=⃗F·⃗v dt=0, because ⃗F⊥⃗v. So the speed, and with it the kinetic energy, stays constant.

But a force perpendicular to the velocity is a centripetal force: it bends the path into a circle (or a helix if the particle also drifts along the field).

Momentum is the vector ⃗p=m⃗v, so turning ⃗v changes ⃗p even though its magnitude is fixed.

So the momentum changes while the kinetic energy does not.

Why the other options are wrong

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