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Asked in GUJCET 2008 · Galvanometer in a balanced circuit
Given: θ₁=50 divisions with no shunt, θ₂=10 divisions once a shunt S=12 Ω is across the coil.
Idea: the current drawn from the circuit is unchanged; the shunt only divides it, and the deflection follows the current in the coil, so (θ₂)/(θ₁)=(I_g)/I.
Current division between coil and shunt: (I_g)/I=S/(S+G).
So (10)/(50)=(12)/(12+G), that is 12+G=60.
G=48 Ω.
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