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The deflection in a moving-coil galvanometer falls from 50 divisions to 10 divisions, when a shunt of 12 Ω is connected with it. The resistance of the galvanometer coil is

Asked in GUJCET 2008 · Galvanometer in a balanced circuit

Answer: (2) 48 Ω

Step-by-step solution

Given: θ₁=50 divisions with no shunt, θ₂=10 divisions once a shunt S=12 Ω is across the coil.

Idea: the current drawn from the circuit is unchanged; the shunt only divides it, and the deflection follows the current in the coil, so (θ₂)/(θ₁)=(I_g)/I.

Current division between coil and shunt: (I_g)/I=S/(S+G).

So (10)/(50)=(12)/(12+G), that is 12+G=60.

G=48 Ω.

Why the other options are wrong

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