Current of 10 A and 2 A are passed through two parallel wires A and B respectively in opposite directions. If the wire A is infinitely long and length of the wire B is 2 m, the force acting on the conductor B which is situated at 10 cm distance from A will be .

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(4) 8×10⁻⁵ N. Given: I₁=10 A in the infinite wire, I₂=2 A in wire B, ℓ=2 m, d=10 cm=0.1 m. Idea: the long wire's field at B is (μ₀I₁)/(2π d), and wire B lies across that field, so F=BI₂ℓ=(μ₀I₁I₂ℓ)/(2π d). (μ₀)/(2π)=2×10⁻⁷ T m A⁻¹. F=2×10⁻⁷×(10×2×2)/(0.1)=8×10⁻⁵ N. The currents are antiparallel, so this 8×10⁻⁵ N pushes the two wires apart.

Current of 10 A and 2 A are passed through two parallel wires A and B respectively in opposite directions. If the wire A is infinitely long and length of the wire B is 2 m, the force acting on the conductor B which is situated at 10 cm distance from A will be ______.

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