If a capacitor of capacitance 1200 μF is charged at a uniform rate of 100 μC s⁻¹, what is the time required to increase its potential by 20 V?

Question

Accepted Answer

(3) 240 s. Given: C=1200 μF, (dQ)/(dt)=100 μC s⁻¹, Δ V=20 V. Idea: the charge needed is Q=C Δ V, and at a steady rate it arrives in t=Q/(dQ/dt). Charge needed: Q=1200 μF×20 V=24 000 μC. Time: t=(24 000)/(100) s=240 s. Equivalently, each volt needs (1200)/(100)=12 s, and 20 volts need 240 s.

If a capacitor of capacitance 1200 μF is charged at a uniform rate of 100 μC s⁻¹, what is the time required to increase its potential by 20 V?

Step-by-step solution

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