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Asked in GSEB Board July 2017 · Capacitor networks
Given: three identical plates of area A, successive gaps d; the two outer plates are joined to a and the middle plate to b (see figure).
Idea: each gap between a plate at a and a plate at b is a parallel-plate capacitor C₀=(ε₀A)/d.
The upper gap lies between an a-plate and the b-plate: one capacitor C₀.
The lower gap does the same: a second capacitor C₀.
Both sit between the same two points a and b, so they are in parallel: C=C₀+C₀=(2ε₀A)/d.
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