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Asked in GSEB Board July 2016 · Relation between field and potential
Given: uniform field ⃗E = E₀ ̂i, and V = 0 at x = 0.
Idea: Eₓ = -(dV)/(dx), so V(x) - V(0) = -∫₀^x E₀ dx.
For a uniform field the integral is simply E₀x, so V(x) = 0 - E₀x.
The sign is negative because the potential falls as we move along the field.
So V = -xE₀.
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