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Asked in GUJCET 2016 · Redistribution of charge
Given: capacitor C with energy U = (Q²)/(2C), isolated, then joined in parallel with an uncharged capacitor 2C.
Idea: the charge Q is conserved, and both capacitors end at the same voltage.
Common voltage: V' = Q/(C + 2C) = Q/(3C).
First: U₁ = 1/2C(Q/(3C))² = 1/9·(Q²)/(2C) = 1/9U.
Second: U₂ = 1/2(2C)(Q/(3C))² = 2/9U.
(Together 1/3U; the other 2/3U is lost as heat and radiation while the charge flows.)
So the energies are 1/9U and 2/9U.
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