An electron is accelerated under a potential difference of 182 V. The maximum velocity of the electron will be . (Charge of electron is 1.6×10⁻¹⁹ C and its mass is 9.1×10⁻³¹ kg.)

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(3) 8×10⁶ m/s. Given: V = 182 V, e = 1.6×10⁻¹⁹ C, m = 9.1×10⁻³¹ kg; the electron starts from rest. Idea: the work done on the electron by the field, eV, becomes its kinetic energy: 1/2mv² = eV. v² = (2eV)/m = (2×1.6×10⁻¹⁹×182)/(9.1×10⁻³¹). (2×1.6×182)/(9.1) = 64, so v² = 64×10¹² m² s⁻². v = 8×10⁶ m/s.

An electron is accelerated under a potential difference of 182 V. The maximum velocity of the electron will be ______. (Charge of electron is 1.6×10⁻¹⁹ C and its mass is 9.1×10⁻³¹ kg.)

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