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The equivalent inductance of two inductors is 2.4 H when they are connected in parallel and 10 H when they are connected in series. The individual inductances are .........

Asked in RS Academy GUJCET booklet · Coil geometry, cores and combinations

Answer: (1) 6 H, 4 H

Step-by-step solution

Given: series L₁+L₂=10 H; parallel (L₁L₂)/(L₁+L₂)=2.4 H.

Idea: with no mutual inductance, inductors combine like resistors; the two conditions fix the sum and the product.

Product: L₁L₂=2.4×10=24 H².

So L₁ and L₂ are the roots of x²-10x+24=0, that is (x-6)(x-4)=0.

So the inductances are 6 H and 4 H.

Why the other options are wrong

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