Practice portal › Electromagnetic Induction › Self-Inductance
Asked in RS Academy GUJCET booklet · Coil geometry, cores and combinations
Given: series L₁+L₂=10 H; parallel (L₁L₂)/(L₁+L₂)=2.4 H.
Idea: with no mutual inductance, inductors combine like resistors; the two conditions fix the sum and the product.
Product: L₁L₂=2.4×10=24 H².
So L₁ and L₂ are the roots of x²-10x+24=0, that is (x-6)(x-4)=0.
So the inductances are 6 H and 4 H.
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