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Asked in RS Academy GUJCET booklet · Gauss's law and enclosed charge
Given: a dipole (+q and -q) at the centre of a sphere, so both charges are inside it.
Idea: Gauss's law, Φ = (q_enc)/(ε₀), where q_enc is the algebraic sum of the charges inside.
q_enc = (+q) + (-q) = 0
Φ = 0/(ε₀) = 0
Field lines leave the sphere near +q and the same number enter near -q; the outward and inward fluxes cancel.
So the total flux through the sphere is zero.
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