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Asked in GSEB Board July 2016 · Coulomb's law and superposition
Given: force in vacuum F; the same charges at the same separation, now in a medium of dielectric constant K.
Idea: in a medium, the permittivity ε₀ in Coulomb's law is replaced by ε=Kε₀.
In vacuum: F=1/(4πε₀)(q₁q₂)/(r²)
In the medium: F'=1/(4π Kε₀)(q₁q₂)/(r²)=F/K
The molecules of the medium polarise and partly screen each charge from the other, which is why the force is reduced.
So the force in the medium is F/K.
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