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Asked in GUJCET 2023 · Electric flux through a surface
Given: ⃗E=3×10³ ̂k N/C; a square of side 0.20 m parallel to the yz plane.
Idea: φ=⃗E·⃗A=EA cos θ, with ⃗A along the normal to the square.
A square parallel to the yz plane has its normal along the x-axis: ⃗A=A ̂i with A=0.04 m².
⃗E is along ̂k, so ⃗E·⃗A=(3×10³)(0.04)(̂k·̂i)=0
The field lines run parallel to the square and none pass through it.
So the flux is zero.
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