Practice portal › Dual Nature of Matter and Radiation › Comparing de Broglie Wavelengths of Particles
Asked in GSEB Board July 2018 · Same or changed energy
Given: λ₁ = 0.5×10⁻¹⁰ m and λ₂ = 10⁻¹⁰ m, so the wavelength must double.
Idea: λ = h/p = h/(√2mK), so for the same electron K ∝ 1/(λ²).
(K₂)/(K₁) = ((λ₁)/(λ₂))² = ((0.5)/1)² = 1/4
Doubling the wavelength needs one-fourth of the energy.
So the energy should be decreased to one-fourth.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer