Practice portal › Current Electricity › Electric Current and Drift Velocity
Asked in RS Academy GUJCET booklet · Drift velocity, mobility and current density
Given: ℓ = 3 m, I = 3 A, A = 2×10⁻⁶ m², n = 8.5×10²⁸ m⁻³, e = 1.6×10⁻¹⁹ C.
Idea: I = neAv_d, so v_d = I/(neA), and the time to cover the length is t = ℓ/(v_d) = (neAℓ)/I.
neA = 8.5×10²⁸×1.6×10⁻¹⁹×2×10⁻⁶ = 2.72×10⁴ C m⁻¹.
t = (2.72×10⁴×3)/3 = 2.72×10⁴ s, about 7.6 hours.
The drift speed is only v_d = 3/(2.72×10⁴) ≈ 1.1×10⁻⁴ m s⁻¹: the electrons crawl, even though the current is set up almost at once.
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