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What will be the time taken by an electron to move with drift velocity from one end to the other end of a copper conductor 3 m long and carrying a current of 3 A? Area of cross-section = 2×10⁻⁶ m² and the number density of free electrons in copper is 8.5×10²⁸ m⁻³.

Asked in RS Academy GUJCET booklet · Drift velocity, mobility and current density

Answer: (2) 2.72×10⁴ s

Step-by-step solution

Given: ℓ = 3 m, I = 3 A, A = 2×10⁻⁶ m², n = 8.5×10²⁸ m⁻³, e = 1.6×10⁻¹⁹ C.

Idea: I = neAv_d, so v_d = I/(neA), and the time to cover the length is t = ℓ/(v_d) = (neAℓ)/I.

neA = 8.5×10²⁸×1.6×10⁻¹⁹×2×10⁻⁶ = 2.72×10⁴ C m⁻¹.

t = (2.72×10⁴×3)/3 = 2.72×10⁴ s, about 7.6 hours.

The drift speed is only v_d = 3/(2.72×10⁴) ≈ 1.1×10⁻⁴ m s⁻¹: the electrons crawl, even though the current is set up almost at once.

Why the other options are wrong

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