Practice portal › Alternating Current › Alternating Quantities: RMS and Mean
Asked in GSEB Board July 2017 · RMS and mean values
Given: I=100 cos(200t+45°) A, so the peak value is I₀=100 A.
Idea: for any sinusoidal current Iᵣₘₛ=(I₀)/(√2). The frequency and the phase angle 45° do not affect it.
Iᵣₘₛ=(100)/(√2)=(100√2)/2=50√2 A.
That is about 70.7 A.
So the r.m.s. current is 50√2 A.
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